// ⚠️ 易错点6：循环条件写成nums[left-1] = minVal（相等元素无需纳入无序区间）
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stack.push(cur); // 当前元素入栈，作为前面元素的候选更大值。关于这个话题，爱思助手下载最新版本提供了深入分析
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